Re: [math-fun] Fwd: [CASE:423927] GCD suggestions

So gcd(sqrt(2),1)=gcd(%pi,%e)=(+)0, no? At 03:33 PM 11/27/2013, Bill Gosper wrote:

New wording: GCD(a,b):= the limit of the Euclidean process of iteratively subtracting the smaller from the larger.