geezer + traum (german for dream) = geezertraum seems to be the construct On Thu, Jan 24, 2019 at 8:47 AM Fred Lunnon <fred.lunnon@gmail.com> wrote:
Yup, that's what he meant! WFL
On 1/24/19, James Propp <jamespropp@gmail.com> wrote:
On Thursday, January 24, 2019, Bill Gosper <billgosper@gmail.com> wrote:
This should enable me to prove the
geezertraum that e and e are algebraically independent.
What did you mean to write here?
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