[Fractint] FOTD 09-11-07 (Child of the Ages [8])

8 Nov 2007

      FOTD -- November 09, 2007 (Rating 8)

Fractal visionaries and enthusiasts:

Today's FOTD is from the same Z^(1.75)+C parent fractal as 
yesterday's.  But today, instead of checking the chaos up north, 
we check the inside shore of the north branch of the valley 
enclosing the large period-2 bud on the east side of the large 
main bay of the parent.

Once I reached the spot, it was not too difficult to find one of 
the minibrots that inhabit the area, and color it appropriately.  
The rating of an 8 shows that I am well satisfied with the final 
result.

The name "Child of the Ages" is simply a phrase that came to 
mind while I was checking to see whether the scene is located on 
the parent or child side of its valley.  It is on the child side.

The sight of the image is worth its calculation time of 6-3/4 
minutes.  But absolute worth is a subjective thing, so for more 
convenience, the finished image is posted for instant viewing on 
the FOTD web site at:

       <http://home.att.net/~Paul.N.Lee/FotD/FotD.html>

Cloudy skies and a temperature of 39F 4C, along with flurries of 
leaves, made Thursday feel quite like autumn here at Fractal 
Central.  The fractal cats were more concerned with the pigeons 
than with the autumn leaves.

My day was busy but under control.  The next FOTD will appear in 
24 hours.  Until then, take care, and are fractals good, evil, 
both, or neither?

Jim Muth
jamth@mindspring.com
jimmuth@aol.com

START PARAMETER FILE=======================================

Child_of_the_Ages  { ; time=0:06:47.33-SF5 on P4-2000
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  formulaname=MandelbrotBC3 function=floor
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frm:MandelbrotBC3   { ; by several Fractint users
  e=p1, a=imag(p2)+100
  p=real(p2)+PI
  q=2*PI*fn1(p/(2*PI))
  r=real(p2)+PI-q
  Z=C=Pixel:
    Z=log(Z)
    IF(imag(Z)>r)
      Z=Z+flip(2*PI)
    ENDIF
    Z=exp(e*(Z+flip(q)))+C
  |Z|<a }

END PARAMETER FILE=========================================