I was guessing when i could start playing game : guess who made the frame, with other. Here is a frame who will set the boundary to another level. Actually proud of being able to get their with my own reaction. image visible at : https://sites.google.com/site/sinpix12823fractal/ START PARAMETER FILE================================== light_of_the_night { ; pentagram different area reset=2004 type=formula formulafile=2012_3.frm formulaname=nop3 corners=-0.3404019665/-0.3391603665/1.0576123432/1.0585435432 params=1/0/6/0 float=y inside=0 colors=000zzN6zzzz9C0C0FF00IH0JGGL<3>BBRAAT99U<3>44`33b11c00e<3>C8aFA_IC\ ZLEYOGX<8>A7E86B759<3>000<8>HFMJGOLIR<3>TP`<3>icYmgXqkWvnWzrVzzV<3>VzV<3\
Vzz<2>Vbzhhz<3>zhz<3>zhh<3>zzh<3>hzh<3>hzz<2>hlz00S<3>S0S<3>S00<3>SS0<3\ 0S0<3>0SS<2>07SEES<3>SES<3>SEE<3>SSE<3>ESE<3>ESS<2>EHSKKS<2>QKSSKSSKQSK\ OSKMSKK<2>SQKSSKQSKOSKMSKKSK<2>KSQKSSKQSKOSKMS00G<3>G0G<3>G00<3>GG0<3>0G\ 0<3>0GG<2>04G88G<2>E8GG8GG8EG8CG8AG88<2>GE8GG8EG8CG8AG88G8<2>8GE8GG8EG8C\ G8AGBBG<2>FBGGBGGBFGBDGBCGBB<2>GFBGGBFGBDGBCGBBGB<2>BGFBGGBFGBDGBCG000<6\ 000 }
frm:nop3{;sinpix a=real(p1)+imag(p1) b=real(p2)+imag(p2) c=sin(a/b) z=c=a/2/(pixel): q=z/(a^z) z=q+a*z^b+sqr(z*flip(z/2)^b)+c |z|<10 } END PARAMETER FILE======================================