Tim, Your mention of POVRay (below) inspires me to inquire if Fractint can be enabled to provide the kind of looks at 3D objects such as are seen in this 'T-set' video at http://ixitol.com/html/videos.html This object, rendered in POVRay, is generated by the formula T-set { x=real(pixel), y=imag(pixel), v=p1 x1=y1=v1=0: a = x1^2 + 2*y1*v1 b = v1^2 + 2*x1*y1 c = y1^2 + 2*x1*v1 x1 = a+x, y1 = b+y, v1 = c+v z = x1^2 + y1^2 + v1^2 z < 100 } Perhaps it is a function of my still limited familiarity with Fractint, but thus far only 2D slices of this object have rendered therein, and those views only in planes perpendicular to one of the three axes. Does Fractint offer functionalities in this respect of which I am yet unaware? If not, would it be possible perhaps to port over some of the pertinent POVRay code? It would be awesome if this kind of 3D imaging were possible "in house". Ciao, Russell ----- Original Message ----- From: "Tim Wegner" <twegner@swbell.net> To: "Fractint and General Fractals Discussion" <fractint@mailman.xmission.com> Subject: Re: [Fractint] quaternion product correction Date: Tue, 25 Oct 2005 21:13:27 -0600
More concerning my correspondence with Wes Loewer.
One of the things that attracted me to Hypercomplex numbers was that there is a general way to calculate a function on the hypercomplex numbers from the analogous complex function. Wes showed me how to do the same thing with quaternions. It isn't quite as elegant, but it's not hard. This means I could add fractal types quaternion and quaternionj that are exact analogues (with equal generality) of the hypercomplex and hypercomplexj types. (These are general because they use a function variable that can be set to a variety of analytic functions.) There are some quaternion types already in fractint but they are less general.
I guess I should check out POVray also for the same generalization possibility.
I'm enjoying the possibility of this project since I haven't contributed any code to fractint for a long time. Jonathan has been holding down the fort by himself.
Tim
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